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Mathematics 14 Online
OpenStudy (anonymous):

108=ab^3 sove for a

OpenStudy (solomonzelman):

divide both sides by b^3

OpenStudy (anonymous):

108/b^3=a

OpenStudy (solomonzelman):

Yup!

OpenStudy (anonymous):

is that the answer?

OpenStudy (solomonzelman):

Yes!

OpenStudy (anonymous):

my textbook says its supposed to be 12/b

OpenStudy (solomonzelman):

Maybe the problem is 108=(ab)^3 that the "a" is also to the third power. Right?

OpenStudy (anonymous):

no, there are no parenthesis

OpenStudy (solomonzelman):

Ok, if the problem is \[\huge\color{blue}{ 108=ab^3 }\]then the answer, as you said, is\[\huge\color{blue}{ a=\frac{108}{b^3} }\]

OpenStudy (anonymous):

thats the online textbook page for the problem

OpenStudy (solomonzelman):

If the problem is \[\huge\color{blue}{ 108=(ab)^3 }\] then\[(108=4 \times 27=4 \times 3^3)~~~~~~~~~~\huge\color{blue}{ 4 \times 3^3=(ab)^3\ }\] \[\huge\color{blue}{ 4=\frac{(ab)^3}{3^3} = \frac{(ab)}{3} }\]Knowing that\[ \frac{ab}{3} =4~~~~~~~~->~~~~~~~ab=12~~~~~~~->~~~~~~a=12/b\]

OpenStudy (solomonzelman):

You link requires login.

OpenStudy (solomonzelman):

your link..:)

OpenStudy (anonymous):

that doesn't, its example 1

OpenStudy (solomonzelman):

Sorry, I don't have an app for that on my comp.

OpenStudy (solomonzelman):

But is it 1 of the two things I posted in blue?

OpenStudy (anonymous):

yes, the first one, but the answer is the answer of the second one

OpenStudy (solomonzelman):

All I know is that to the first one the answer is 108/b^3 and to the second one I posted is 12/b

OpenStudy (anonymous):

Screen Shot 2014-02-09 at 6.43.08 PM

OpenStudy (anonymous):

can u open that?

OpenStudy (solomonzelman):

Sorry, no.

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