At time t in seconds, a particle’s distance s(t), in micrometers, from a point is given by s(t)=(e^t) - 1. What is the average velocity of the particle from t=2 to t=5?
(round to 3 decimal places)

how do I solve this? :/

Question

At time t in seconds, a particle’s distance s(t), in micrometers, from a point is given by s(t)=(e^t) - 1. What is the average velocity of the particle from t=2 to t=5?
(round to 3 decimal places)

how do I solve this? :/

anonymous · Answer

average velocity = [s(5) - s(2)]/(5 - 2) = distance/time

anonymous · Answer

so simplifies to 

s(5)-s(2)          ((e^5)-1) - ((e^2)-1)
_________   =  _____________________
   3                                  3

??

anonymous · Answer

i don't quite understand what you mean:(

where did you get those values from?

jim_thompson5910 · Answer

that looks like a completely different problem

now just evaluate ((e^5)-1) - ((e^2)-1) all over 3 with a calculator

jim_thompson5910 · Answer

and round to 3 decimal places

anonymous · Answer

47.008 ?

jim_thompson5910 · Answer

good 47.0080343346338 turns into 47.008

anonymous · Answer

okay yay!! thank you!!!

anonymous · Answer

Somehow two problems have gotten entwined. I will delete my stuff.

anonymous · Answer

hahaa okay:P