At time t in seconds, a particle’s distance s(t), in micrometers, from a point is given by s(t)=11sin t + 34. What is the average velocity of the particle from t=π/3 to t=13π/3?
(round to 3 decimal places!)

would it start off like this?
s(13π/3)-s(π/3)
________________
(13π/3 - π/3)

??? :/

Question

At time t in seconds, a particle’s distance s(t), in micrometers, from a point is given by s(t)=11sin t + 34. What is the average velocity of the particle from t=π/3 to t=13π/3?
(round to 3 decimal places!)

would it start off like this?
s(13π/3)-s(π/3)
________________
(13π/3 - π/3) 

??? :/

jim_thompson5910 · Answer

good, keep going

jim_thompson5910 · Answer

so you'll have


[11*sin(13π/3) + 34] - [11*sin(π/3) + 34]
---------------------------------------
                            13π/3 - π/3

jim_thompson5910 · Answer

evaluate that with a calculator (make sure you are in radian mode)

anonymous · Answer

i got 39.28180995

so about 39.282 ?

is that correct?

jim_thompson5910 · Answer

no it's not

anonymous · Answer

aww okay.. lemme try again.. one sec :)

anonymous · Answer

i got 0/13π/3 - π/3=-1.047197551

so about -1.047 ? 

is that right this time? :/

jim_thompson5910 · Answer

still not correct

anonymous · Answer

aww :/ okay.. not sure what i'm doing wrong..

it's in radian mode :/ 
 

i'll do it step by step what i get.. one sec:)

anonymous · Answer

[11*sin(13π/3) + 34] - [11*sin(π/3) + 34]
---------------------------------------
                            13π/3 - π/3

=(43.52627944) - (43.52627944)
---------------------------------
    (13.61356817) - (1.047197551) 

=               0
---------------------
       12.56637062

=0

? :/

anonymous · Answer

not sure how i keep getting different values lol :/ hopefully this one's right? :/

jim_thompson5910 · Answer

0 is correct

anonymous · Answer

ohh yay!!! :) 3rd times the charm i guess lol :p

thank you!!