Find an equation of the line. Perpendicular to y=3x+5; through (1,0). Write the equation in Standard Form.

Question

anonymous · Answer

Your original equation is given is y = mx + b form. In this form m = 3 is your slope. Perpendicular lines have opposite reciprocal slopes (not a complicated as it sounds). Basically flip the slope over and multiply by -1.
So the new slope becomes -1/3. Now you have a slope and a point, begging for point slope form: y - y1 = m(x - x1). From there, you need to convert to standard form.

anonymous · Answer

so does y=-1/3 ?

anonymous · Answer

No, your slope is -1/3.

anonymous · Answer

$$y-0=-\frac{1}{3}(x-1)$$ is the point slope form
or just 
$$y=-\frac{1}{3}(x-1)$$ 
multiply out if you like

anonymous · Answer

ooh standard form, i should learn to read 
$$y=-\frac{1}{3}(x-1)$$ multiply both sides by $-3$ and get 
$$-3y=x-1$$

anonymous · Answer

which you can then rewrite as 
$$x+3y=1$$ if you like

anonymous · Answer

i'm very confused ;_;