Question

please help

Answer 1

\[4+\sqrt{(-4)^{2}}-\frac{ 4(1)(3) }{ 2(1) }\]
like this?

Answer 2

Can you draw or use the equation function to show it to me?
It's a little confusing.

Answer 3

that is just the quadratic formula for something.

Answer 4

i just did it. and its not -6. show me your steps. and we can help correct your mistakes

Answer 5

what do you get under the radical?

Answer 6

did you give up?

Answer 7

tell me what you have under the radical. or square root sign.

Answer 8

or we can do this in steps. do you know what (-4)^2 is?

Answer 9

ok so what is -4(1)(3)

Answer 10

ok so what is 16-12

Answer 11

4

Answer 12

ok. so to answer my question. there is a 4 under the radical.
what is sqrt4

Answer 13

ok so in the numerator you have 4+2. what is that

Answer 14

okay, so it's:
\[\frac{ 4+\sqrt{(-4)^{2}-4(1)(3)} }{ 2(1) }\]
Let's first begin by solving what's inside the radical (square root), I'll let you know something tht may be too early but I'll state it:
\[a \epsilon R\]
\[(a)^{2}=a ^{2}\]
\[(-a)^{2}=a ^{2}\]
With that, I mean that "a" belonging to the real numbers, does not matter if it's negative or positive, the result we get by squaring it is always positive.
It has a proof, but we can logically tell that because, after all, (-)x(-) = (+) .
So that does mean that (-4)^2=16.
\[\frac{ 4+\sqrt{(-4)^{2}-4(1)(3)} }{ 2(1) }\]
\[\frac{ 4+\sqrt{16-4(1)(3)} }{ 2(1) }\]
Let's now solve those multiplications:
\[\frac{ 4+\sqrt{16-12} }{ 2 }\]
\[(-4(1)(3)=-12)\]
So, let's continue by solving the difference in the radical:
\[\frac{ 4+\sqrt{4} }{ 2 }\]
\[(16-12=4)\]
Now square root of 4 is equal to 2, and the rest is just a matter of operating:
\[\frac{ 4+\sqrt{4} }{ 2 }\]
\[\frac{ 4+2 }{ 2 }\]
\[(\sqrt{4}=2)\]
\[\frac{ 6 }{ 2 }=3\]

Answer 15

thanks for doing his homework for him.

Answer 16

Wowza, I'm going to copy all this down. I know where my steps went wrong.
Thanks mate! @Owlcoffee

@lonnie455rich This was the second answer I had in mind but I didn't think I was correct at all. He actually helped me.

Answer 17

You are in no position for telling me how to help or teach, your explainations lack content and the fundamentals, does not matter if I did it.

Answer 18

i don't see where anything needed explained. i asked him questions. he gave correct answers.

Answer 19

You can question somebody as much as you wish, but I dislike when people teach or tutor maths by questions.
That destroys the essence of learning and teaching, but... That's just me.

Answer 20

i need to know what they know. so i know, that theyre working instead of just getting the answer. that is my point. im not here to teach. they have teachers for that. i just try to help guide people when theyre having a block or something. and he was just making a silly mistake im sure. because he didnt make one once we broke it down into simple steps.

Answer 21

I see, that's a very basic way of looking at it.
Your sight became a flaw when you said "They have teachers for that", at least to me.
Learning is something we do all the time, even when it comes to mathematics.
Even when we are at school, our knowledge is something we work out for ourselves, a teacher will never teach you various things.
Even if he made a silly mistake, I showed him using his exercise as an example, because I have confidence that he won't stumble upon the same stone again.

Answer 22

one thing to consider.. is 90% of the people here just want answers. not that that was the op's motives. just that's the trend.