Question

17 minutes after a man leaves for his morning jog, his wife leaves for a bike ride along the same road. The man jogs at an average rate of 3 mph. At what minimum rate should the wife bike to catch up with her husband within 30 minutes?

Answer 1

Do you know the concept of relative motion ??

Answer 2

i'm just not sure how to set this up into an equation.

Answer 3

Fist tell me, are you aware of relative motion ?

Answer 4

no

Answer 5

Okay..

"At what minimum rate should the wife bike to catch up with her husband within 30 minutes?"
I am not sure if the "within 30 min" is from the time when the wife leaves the home or the man. Can you please clarify ??

Answer 6

30 minutes from when the wife leaves.

Answer 7

Now, can you find the distance traveled by the man in time (17 + 3) min ??

Answer 8

* (17 + 30) min

Answer 9

distance = rate * time

man jogs for 47 min
D = 3*(47/60)

wife bikes for 30 min and goes same distance
D = (30/60)v = 3*(47/60)

solve for v

Answer 10

v = 2.35

Answer 11

no

(1/2) v = 2.35

Answer 12

the wife can't go slower then she will never catch up

Answer 13

so it is 4.7

Answer 14

thank you

Answer 15

yep

yw

Answer 16

i didn't get that
distance in miles= velocity in mph times time in hours
d = vt
for the man d = 3(30/60) = 1.5 miles
for the woman, meeting in 30 minutes
she waited 17 minutes so she only has (30-17) 13 minutes to travel 1.5 miles
1.5 = v (13/60)
v = 1.5(60)/13
v = 7

Answer 17

@triciaal
30 minute period is taken from the time the wife leaves the home.

Answer 18

i understand what you did but the question said she wanted to catch up with him within 30 mins so she only had the 13 minutes to bike

Answer 19

I asked willowtrain to clarify this point; and he replied "30 minutes from when the wife leaves. "

Answer 20

spanish is so much easier than english!

Answer 21

LOL

Answer 22

English is my only language, sorry