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Chemistry 13 Online
OpenStudy (anonymous):

plz can someone help me?

OpenStudy (anonymous):

I would use the unit-factor method to solve this question, but formulas are easier to write about. The relevant formula to use is: Q = (CP)(delta-T)(n) where Q is the heat energy transferred into or out of a material, CP is the heat capacity of the material, delta-T is the temperature change, and n is the number of moles. If the heat capacity were given on a mass-basis (as a specific heat capacity of a specific heat) then the mass m would be used instead of the number of moles n. In this case, we're told that the temperature of sodium can't increase by more than 10.0 °C. A change of 10.0 °C is the same as a change of 10 K. We need to convert megajoules to Joules. Solving for n yields: n = Q/((CP)(delta-T)) = (8.30X106 J)/((30.8 J/(K·mol))(10.0 K)) = 2.69X104 moles of Na . Convert to grams of Na for your final answer. http://www.wyzant.com/resources/answers/17701/liquid_sodium_is_being_considered_as_an_engine_coolant_how_many_grams_of_liquid_sodium_minimum_are_n

OpenStudy (anonymous):

Also a previous asked question http://openstudy.com/study#/updates/50132cd7e4b0fa24672fff79

OpenStudy (anonymous):

thank you so much for the link @sarah786. it was very helpful :)

OpenStudy (anonymous):

yw :)

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