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Chemistry 18 Online
OpenStudy (anonymous):

Does anyone know how to solve this problem?

OpenStudy (anonymous):

1 mole of KCN = 65.116 g to find how many moles in 7 g 7g/65.116g/mole = 0.10750g

OpenStudy (anonymous):

Second step 2.859kJ/K^-1 x .440K = 1.25796kJ for one mole 1.25796 kJ/ .10750mol = 11/70 kJ/mol

OpenStudy (anonymous):

11.70kJ/mol* Answer

OpenStudy (anonymous):

wow!!! u make it seem so easy!! thank you again!

OpenStudy (anonymous):

yw :)

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