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Chemistry 7 Online
OpenStudy (anonymous):

help plz

OpenStudy (anonymous):

wait . Can you show me your work too ???

OpenStudy (anonymous):

im attachin my work .

OpenStudy (anonymous):

u have the density of the solution so u can find the mass(m) of the solution.u also have its specific heat(s).now H for this reaction for the given temperature change can be given by H=m x s x change in temperature the reaction is------------>Ba(OH)2 + 2HCl -->BaCl2 + 2H2O now considering the no. of moles of the reactants,find the moles of water(n) and divide H by n to get the answer

OpenStudy (anonymous):

So i assumed that this is a molarity problem where using the molarity formula (first converted ml to L) i found that there is 21000 moles of the Ba... solution and 42000moles of the HCl solution... am i going in the right direction?

OpenStudy (anonymous):

it is same example like in my book but values are changed . but that per moles H2O .Confusin me still . @Rohitkhanna Can you please check IS my work correct or not ??? I dun wanna give anyone incorrect answers .

OpenStudy (anonymous):

i am just a bit unsure about ur step when u got 0.06 moles of both.wanna know how u came up with it??????@sarah786

OpenStudy (anonymous):

as Ba(OH)2 means 2OH so .3 x 2 = .6 moles

OpenStudy (anonymous):

hm.... i got a really big number... like 5.4*10^5... yikes seems unrealistic.

OpenStudy (anonymous):

so 70cm3 of .6 M solutions = .06 moles of both because .6 M solution means that 1000 cm3 of solution has .6 moles of solute ops I got where I went wrong my BAd its .04 moles for each

OpenStudy (anonymous):

molarity=no. of moles/given volume(in litres) 0.3=n/(70/1000) n=0.021 for Ba(OH)2 for HCl n=0.042 as required per the equation,Hcl has twice the no. of moles than Ba(OH)2 so the reaction would consume them totally now 2 x no. of moles of HCl=2 x no. of moles of water as seen by the equation of this reaction no. of moles of water=0.042 so now divide H by 0.042 to get the correct answer

OpenStudy (anonymous):

did u get it now???@lulu456

OpenStudy (anonymous):

yup its .04 moles for each as @Rohitkhanna mentioned . then ur answer will be 51.45 kJ/mol

OpenStudy (anonymous):

@lulu456 are u there??????????

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