Question

Find the height, in feet, of the ball after 3 seconds in the air?

help?a ball is launched from a sling shot. its height, h(x), can be represented by a quadratic function in terms of time,x,in seconds.

After 1second, the ball is 121 feet in the air, after 2 seconds, it is 224 feet in the air.

Answer 1

This is similar to previous question.
Assume a general quadratic equation & make three equations with three unknown variables.

Answer 2

ok

Answer 3

Tell me the three equations; so that I can check them :)

Answer 4

What was your general quadratic equation ??

Answer 5

what do you mean?
this?
h(x)=ax^2+mx+b?

Answer 6

In that case;
h(1) = a(1^2) + m(1) + b = 121

Answer 7

h(1)=a1^2+m1+b
h(2)=a2^2+m2+b
h(3)=a3^2+m3+b

Answer 8

As we don't have a value for h(3) ; we can use it to deduce the function h.
Read the question again and try to find one more equation.

Answer 9

im not finding it?

Answer 10

uggghhh i suck at this /.\

Answer 11

is the answer 327?

Answer 12

OS was down for me last night..then I went to sleep..

At time t = 0; distance traveled = 0 ; thus
h(0) = a(0^2) + m(0) + b = 0
Hence, b = 0

So we are left with two equations and two unknowns.
a(1^2) + m(1) = 121
a(2^2) + m(2) = 224

Find a and m

Finally calculate h(3)

Answer 13

32 is NOT the correct answer.
See http://www.wolframalpha.com/input/?i=x+%2B+y+%3D+121+%3B+4x+%2B+2y+%3D+224+%3B+9x+%2B+3y+%3D+z

Answer 14

god i suck at this

Answer 15

First of all; fan me coz I can't reply your PMs..

Also, can you tell me where you are stuck ??

Answer 16

im on a different problem but i dont know what to do after you get your 3 equations

Answer 17

Can you tell me the question and your equations..

Answer 18

photo necessities produce camera cases. they have found that the cost, C(x) of making x camera cases is a quadratic function in the terms of x. the company also discovered that it costs $23 to produce 2 cases $103 to produce 4 cases and $631 to produce 10 cases. complete the function that represents the cost, C(x) to produce x camera cases

Answer 19

C(x)=2a^2+m2+b
C(x)=4a^2+m4+b
C(x)=10a^2+m10+b

Answer 20

First, you should explicitly write the function -
\[C(x) = ax^2+mx+b\]

Now, can you see the (typographical) mistake in your equations. Also, replace C(2), C(4), C(10) with their respective values..

Please, re-write the equations.

Answer 21

C(2)=2a^2+m2+b
C(4)=4a^2+m4+b
C(10)=10a^2+m10+b

Answer 22

so whats do i do now?

Answer 23

Actually, the equations should be
\[C(2) = a(2^2) + m(2) + b\]
\[C(4) = a(4^2) + m(4) + b\]
\[C(10) = a(10^2) + m(10) + b\]

Answer 24

We already know that
C(2) = 23
C(4) = 103
C(10) = 631

So replace these values in the above equations and tell me what you get.

Answer 25

23=a(22)+m(2)+b

103=a(42)+m(4)+b

631=a(102)+m(10)+b

Answer 26

Er..
\[a^2 = a*a\]

Answer 27

So,
\[2^2 \neq 22\]

Answer 28

thats 4

Answer 29

Yea, can you re-write the equations ??