Question

Find the cross product and show it is orthogonal to both u and v.

u= 6k
v= -i+3j+k

Answer 1

This is the answer I got. I dont know if its correct or not. Can someone help?

Answer 2

you are in right way
but for orthogonality
you may show
u*v =||u|| ||v|| sin (u,v)
find sin (u,v)
it must be 1
because sin pi/2=1

Answer 3

Can you show me how? I want to make sure I am doing the steps correctly.Also, is the answer I got correct?

Answer 4

name u*v=a
find a.u
it will be zero
then you shoe a has right angle with u
also do for a and v

Answer 5

So the answer is.....

sqrt -10j
--------
10

Answer 6

u*v=-18 i -6j +0k

(u*v).u=(-18 i -6j +0k).( 6k )=0
so
(u*v).v=(-18 i -6j +0k) .(-i+3j+k )=+18-18 =0

Answer 7

I dont think that is the cross product? That is what it is asking me to find. Im confused :0

Answer 8

you calculate the cross product correct
u*v=-18i -6j +0k

so
now to show orthogonality between u*v and v use the dot product
if dot product goes to zero so they are orthogonal

Answer 9

The answer is 1?

Answer 10

I got that the cross product is 0.