The legs of a right triangle are lengths x and x√3. The cosine of the smallest angle of the triangle is _____. 1/2 √3 (√3)/2 2√3
help please
do you know the law of cosine?
yes cos= adj/hypo
@NooriK.
the law is \[\cos a = \frac{ B^2 + C^2 - A^2 }{ 2bc }\] A,B and C are the legs of the triangle a,b and c are the angles of the triangle
okay so how can I use the info they gave to solve this equation?
sorry i got drifted away, it's like you have said cos = adj / hyp then you would divide \[\cos = \frac{ x }{ x \sqrt{3} }\]
you cant have root 3 on the bottom so its x root 3/3x?
or do the x's cancel out?
in the question you haven't told which one is the adj and which is the hyp, so i suppose it would be the opposite \[\cos = x \sqrt{3}/x\] but in other problems you have to draw the triangle to solve the problem, or you'll get wasted, the i'm right now XD
wait what?
you have to draw the triangle like|dw:1392068187751:dw| then it would be solved or you'll get lost
without drawing it would be hard to solve
can you solve it?
\[\cos = adj/hypo = x \sqrt{3}/x = \sqrt{3}\]
so the x's cancel out giving us root 3 as the answer?
indeed
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