The line that passes through (1, 5) and (-2, 3) in standard form
"standard form" ? Do you mean Ax + By = C ? Anyways, so first find the slope, M = y2-y1/x2-x1 M = 3-5 / -2 - 1 M = -2 / -3 So your slope is 2/3 Now plug in y-y1=M(x-x1) y - 5 = 2/3(x-1) y - 5 = 2/3x - 0.666 +5 +5 y = 2/3x + 4.33 I don't know what you mean by standard form
That is standard form @tHe_FiZiCx99 .
Input in standard form the equation of the given line. The line that passes through (1, 5) and (-2, 3) that was the question I was given..
Okay, first off. Find the slope of the two pairs of coordinates. \[slope = m = \frac{ y_2-y_1 }{ x_2-x_1 }\] \[m = \frac{ 3-5 }{ -2-1 } = \frac{ -2 }{ -3 } = \frac{ 2 }{ 3 }\] Then use the formula \[y - y_1 = m(x-x_1)\]
\[y - 5 = \frac{ 2(x-1) }{ 3 }\] Multiply both sides by 3. \[3y - 15 = 2x - 2\] Change to standard form of \[ax +by = c\] \[-2x+ 3y = 13\]
Find the slope of the line whose equation is 7y = 3x + 1
7y = 3x +1 Remember the formula for slope-intercept is: \[y = mx + b\] where m = slope So, isolate y. \[\frac{ 7y }{ 7 } = \frac{ 3x }{ 7 } + \frac{ 3 }{ 7 }\] \[y = \frac{ 3 }{ 7 } x + \frac{ 3 }{ 7 }\] So slope = m = 3/7
John made a rectangle pen for his dog using 28 feet of fencing. If the width of the pen is 2 feet more than one-half the length, what is the length and width of the pen? The length of the pen is
Rectangle perimeter = 28 ft width = 2 + 1/2(L) Perimeter = 2L + 2W so 28 = 2L + 2(2+1/2(L)) 28 = 2L + 4 + L 24 = 3L 8 = L W = 2 + (1/2)L W = 2 + (1/2)8 W = 2 + 4 W = 6
Find the slope of the line passing through the points (3, 8) and (-2, 5)
Use the slope formula I posted above.
I did.. I got .6 & that's not an answer on my choices..
.6 = 6/10 = 3/5
Oh, lol. I feel so dumb!
2x+y=7 5x+y=9 Solve the system of equations
y = -2x + 7 5x + (-2x +7) = 9 3x = 2 x= 2/3 y = -2(2/3) + 7 y = -4/3 + 7 y = -4/3 + 21/3 y = 17/3
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you noob.
Me? you did his hw =.= nub
i got bored
o.0
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