Question

i dentify the limiting reactant in the following situation and tell how many grams of excess reactant will remain 72.06g of water and 60.05 g of carbon react to form methane and carbon dioxide I will give a medal to anyone who answers it :)

Answer 1

First write out the balanced chemical equation. Then, find the number of moles of water and CO2. I will help you more from there.

Answer 2

ok 2c+2h20____ch4+co2

Answer 3

Ok so now can you find the number of moles of C and H2O?

Answer 4

how

Answer 5

to get the medal u have to show work n give final answer

Answer 6

I am walking you through it. It is how OpenStudy works. Number of moles is found by dividing the mass with molar mass. You can get the molar mass by referring to a periodic table. http://www.ptable.com/

Answer 7

ok for the atomic masses added up i got 58.036
is that correct

Answer 8

Is that for water or carbon? O.o I don't think it's right.

Answer 9

both of them added up

Answer 10

carbon is 24.02

Answer 11

No no you have to do them separately. You still wouldn't get 58 though...

Carbon is just 12. H is 1 and O is 16. But do them separately according to the substance.

Answer 12

but theirs 2 hydrogens and 2 oxygens

Answer 13

The formula for water is \[H _{2}O\] meaning 2 hydrogen and 1 oxygen

Answer 14

ok so for water i got 33.008

Answer 15

...it should be (1)2+16

Answer 16

?? no hydrogen is 1.008

Answer 17

and oxygen is 16.00

Answer 18

Well ok then (1.008)2+16.00

Answer 19

right

Answer 20

So the molar mass of water is...?

Answer 21

17.008

Answer 22

There are 2 hydrogens so you will have to multiply the mass of hydrogen found in the table by 2.

Answer 23

ups i for got ok so its 18.016