Question

solve 2x-3/x + 4 = x - 3/x

Answer 1

\[\frac{2x-3}{x+4}=\frac{x-3}{x}\] start by cross multiplying to get
\[x(2x-3)=(x+4)(x-3)\] and solve that one

Answer 2

sorry i think u misinterpreted my equation. it is (2x-3) / (x) + (4) = (x) - 3/(x)

Answer 3

i'm in pre calculus

Answer 4

my directions are solve the equation

Answer 5

perhaps
\[\frac{2x-3}{x}+4=x-\frac{3}{x}\] like that?

Answer 6

exactly

Answer 7

since \(x\) cannot be equal to zero, multiply both sides by \(x\) and start with
\[2x-3+4x=x^2-3\] and solve that one

Answer 8

6x = x^2

Answer 9

what do i do from here?

Answer 10

r u there?

Answer 11

\[6x = x^2
\]
\[x^2-6x=0\]
\[x(x-6)=0\] so \(x=0\) which is impossible or \(x=6\)

Answer 12

got it! THANKS