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Mathematics 8 Online
OpenStudy (anonymous):

Help Please @ganeshie8

OpenStudy (anonymous):

OpenStudy (anonymous):

Looking for the missing side?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok i this dont knw how to find the hypotenuse

OpenStudy (anonymous):

\[c^2 = a^2+b^2\] a =24 b = ? c = 25 Plug in the values \[25^2= 24^2+b^2\] Square 25 and 24\[625 = 576+ b^2\] We need to get b^2 by it self so subtract 576 form both sides \[49 = b^2\] To find b, when need to get rid of the square. To do that take the square root of both sides. What is the square root of 49? \[\sqrt{49}\]

OpenStudy (anonymous):

We aren't looking for the hypotenuse in this problem. Hypotenuse is the longest side of the triangle. We are just looking for a side of a leg

OpenStudy (anonymous):

can u help me with one moe @ryan88

OpenStudy (anonymous):

I can try

OpenStudy (anonymous):

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OpenStudy (anonymous):

i got its 113 and what it mean to leave it in radical form

OpenStudy (anonymous):

\[c^2 = a^2 + b^2\] a = 7; b = 8; c = ? Plug in the values\[c^2 = 7^2+8^2\]square the 7 and 8\[c^2 = 49 +64\] Combine like terms\[c^2 = 113\] take the square of both sides to get c by it self\[c = \sqrt{113}\]

OpenStudy (anonymous):

thank u

OpenStudy (anonymous):

It means to leave it as a square root. Like I did

OpenStudy (anonymous):

No problem glad to help

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