Question

Use the product rule to find the derivative of
y= (2x-3)(sqrt x - 1)

Answer 1

product rule states
y' = u'v + uv'

Answer 2

but you're probably going to need more than the product rule in the problem you're solving
it also requires you to use chain rule because of the sqrt(x-1)

Answer 3

I've given you the value of u' already
now, it's your turn to finish the problem

Answer 4

Thanks for the help! I really appreciate it! :) But I'm pretty lost.

Answer 5

open the brackets first... den apply chain rule.. its easy...

Answer 6

product rule^

Answer 7

Okay, actually I followed that first step you did. I just don't know where to go next

Answer 8

study product rule and chain rule.. i can tell the answer but it wont b useful for u... practice some product rule and chain rule ques.

Answer 9

The problem is that we haven't learned about the chain rule yet! :/ That's the next section we are doing though! So I'm having a hard time proceeding with this question.

Answer 10

chain rule is a combination of rules really

Answer 11

you follow the sequence like with higher order of operations
example
sqrt(2x^3 + 1)
can be rewritten into (2x^3 +1)^(1/2)
first apply exponents outside - the ^(1/2), this means you need a power rule
1/2 (2x^3+1)
then you obtain the derivative of whatever is inside the radical - the 2x^3 + 1
6x^2
now combine them by means of multiplication
1/2 (2x^3+1) * 6x^2
simplify further and you're done

Answer 12

so go back to what the product rule says
y' = u'v + uv'
y= (2x-3)(sqrt x - 1), y'=?
substitute the following
(2x-3) = u, then u' = 2
sqrt(x-1) = v, then v' = 1/2sqrt(x-1)^2

Answer 13

I am not sure if you're using a Leibniz notation, and sorry for not using it :)

Answer 14

https://www.math.ucdavis.edu/~kouba/CalcOneDIRECTORY/chainruledirectory/ChainRule.html

Answer 15

Ohhhhh. Okay gotcha! Sometimes I just have to have people walk me through the problem every now and then. I really appreciate your help! :) I'll take a look at that link as well!