Question

Two trains each make a journey of 330km. One of the train travels 5km/h faster than the other and takes 30 min less time. Find the speed of the trains.

Answer 1

330 = vt
330 = (v+5)(t - 0.5)

Answer 2

You have two velocities, \(x\) and \(y\).
Our equations are:\[
y=x+5
\]And \[
\frac{x}{330} + \frac{30}{60}= \frac{y}{330}
\]

Answer 3

Whoops, I should have put \[
\frac{330}{x}+\frac{30}{60}=\frac{330}{y}
\]Since \(d=vt \implies t=d/v\)

Answer 4

let speed of first train be s1,and time t1
330=s1*t1-->1
second
330=(s1+5)(t1-0.5)--->2
solve this two eqn