Question

In a spring system, there are two springs in series with a suspended mass of 6.0kg.
The upper spring has a stiffness of 1100N/m and the lower spring 500N/m. Find the natural frequency of the vertical vibration.

Answer 1

first of all you need to find the the equivalent spring constant for the resulting
oscillations
the springs are in a series combination so, we apply the formula
1/keq. = 1/k1 + 1/k2
where keq is the equvalent spring constant
so by using this formula , we get, keq=343.75
the formula for frequency is\[\sqrt{k/m}\]
so the frequency comes out to be 7.59 approx.
i hope this helps you.

Answer 2

Thank you rajat97

Answer 3

you're welcome
and thanks for the medal:)