Question

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

11 L
15 L
25 L

Answer 1

@sarah786 @ikram002p

Answer 2

@chanelalgr

Answer 3

How much pure water must be mixed with 10 liters of a 25% acid solution to
reduce it to a 10% acid solution?
:
let w = amt of water required to accomplish this
:
The amt of acid will remain the same only the water will increase, lowering the percent
:
.25(10) = .10(w+10)
2.5 = .10w + 1
2.5 - 1 = .1w
1.5 = .1w
w = 1.5/.1
w = 15 liters of water
@Elijah16

Source:Algebra .com

Answer 4

Thanks!

Answer 5

yw ^-^