Question

What is the probability of picking 2 same letters and one different letter from the word 'enlargement' if its picked without replacement?
As there are 3 Es and 2 Ns,
it leaves us with EEx, xEE, ExE, NNx,NxN,xNN
So i did the math for each probability, adding them as they are mutually exclusive and got 1/5. Even though impretty sure its correct, it'll be awesome if someone could verify :)
[3(3/11*2/10*8/9) + [3(2/11*1/10*1)]]
This is how i got 1/5. Please verify :)

Answer 1

@ganeshie8 ,@UnkleRhaukus @shamil98 @Preetha @wolfe8
Help please someone :)

Answer 2

https://www.mathway.com/

Answer 3

this looks extremely confusing, lol, good luck, I hope that helps somewhat c:

Answer 4

Haha its okay thanks :)

Answer 5

@kirbykirby @sarah786 @happinessbreaksbones @michelle_DrNiah
Help please

Answer 6

really no Idea . Sorry :(

Answer 7

Oh, its okay :) Thanks :)

Answer 8

I would love to help, but as it is worded so oddly, I am not entirely sure that I could guide you effectively to an answer in the time that I have currently.
My apologies. If it is still up later, I may be able to help.

Answer 9

Lets assume there are 11 cards, each one has a letter on it, and it basically spells enlargement. We randomly pick the cards. We have to find the probability that the cards we pick end up having exactly 2 letters which are the same, and one which isnt. Order irrelevent.

Answer 10

26 letters in the alphabet.

Answer 11

Omg.haha. No i mean, the letters E N L A R G E M E N T on 11 different cards

Answer 12

@phi @johnweldon1993 @Jamierox4ev3r
Somebody please confirm this for me :)

Answer 13

that is some confusing stuff.

Answer 14

[(3C2)(8C1) + (2C2)(9C1) ] / (11C3) = 1/5

correct

Answer 15

Thanks a lot, took me 2 days to get an answer for this =.=
My friends were trolling me telling me its 3/5. I dropped my pellet for this haha
thank you so much :D

Answer 16

though 1/5 is correct, but your argument is invalid when you said EEx, xEE, ExE, NNx,NxN,xNN. Order does not matter in this case

Answer 17

No but if i draw a tree diagram for simplicity, wouldnt i actaully have the option

Haha sorry the tree diagram sucks, but the possibilities in order would be, E,then E again then some random letter, and that could happen in any order, and the very same thing could happen with N as well,
thus those would be the possibilities in whatever order appropriate to get the possibilities i believe.