Question

please help, question below..

Answer 1

Happy Birthday! Or maybe Happy Un–Birthday? Either way, here is a fun birthday trick.

Take the month you were born in. Multiply it by 4, add 13, multiply by 25, subtract 200, add the day you were born, multiply by 2, subtract 40, multiply by 50, add the last two digits of your birth year, subtract 10500…. viola! Your birth date! Impress your friends!

Now, use your birthday for some more math fun.

You can locate graph paper here.

1. Create a quadratic function, f(x), in vertex form. The a should be between 4 and –4, the h will be your birth month, and the k will be your birth day. Write your equation below.

Answer 2

@agent0smith

Answer 3

i was born june 1 1997 @ranga

Answer 4

Quadratic function f(x), in vertex form is: f(x) = a(x - h)^2 + k
where (h,k) is the vertex.
With birthday, 06/01/1997, h = 6, k = 1
-4 < a < 4. You can let a be 2.
f(x) = 2(x - 6)^2 + 1

Answer 5

#2.
Using complete sentences, explain how to convert your birthday function into standard form.

Answer 6

this is the stuff i dont get.

Answer 7

@ranga

Answer 8

f(x) = 2(x - 6)^2 + 1
The standard form looks like this: ax^2 + bx + c
To convert the vertex form to standard form, first expand the (x-6)^2, multiply by 2 and simplify. Arrange the terms in the order x^2, then x and then the constant.

Answer 9

#3

Create two additional quadratic functions, g(x) and h(x).
The function g(x) will open the same direction as f(x), have the same vertex, but will be narrower.
The function h(x) will open in the opposite direction as f(x), have the same vertex, but will be wider than f(x).
Write your functions below and explain in complete sentences why those functions will meet the requirements in the question.

Answer 10

f(x) = 2(x - 6)^2 + 1
The standard vertex form is: a(x-h)^2 + k
where (h,k) is the vertex.
If "a" is increased, the graph will get narrower.
They want g(x) to have the same vertex and therefore (h,k) will still be (6,1)

g(x) = 3(x - 6)^2 + 1

Since a is positive for both f(x) and g(x), both will be a parabola that opens upward.

To have the graph open downwards, "a" has to be negative.
h(x) will have the same vertex but will be wider than f(x) and will open downwards.
To make it wider, decrease a.
We can choose a as 1 but make it negative so it opens downwards:
h(x) = -1(x - 6)^2 + 1

Answer 11

#4
Graph your functions. Include your graph below.

Answer 12

@ranga

Answer 13

In each case, the vertex is the same. First plot the vertex. Draw a parabola for f(x). Then draw another parabola for g(x) but make it narrower. Then plot h(x) which will be an upside down parabola but will be wider than f(x).

Answer 14

i really dont know how...

Answer 15

The vertex for all three parabolas is (6,1)