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Chemistry 8 Online
OpenStudy (anonymous):

how to balance c12h22011

OpenStudy (abb0t):

This makes no sense whatsoever.

OpenStudy (wolfe8):

True ^ I think you got your question wrong

OpenStudy (anonymous):

well this is one of my questions i put it down the same as it is on the page sooo ?

OpenStudy (wolfe8):

._. What is there to balance?

OpenStudy (anonymous):

well i dont know this is just what it says

OpenStudy (abb0t):

Well, there's nothing to do here.

OpenStudy (anonymous):

c12h22o22+ o2= co2+ h2o sorry theres the rest

OpenStudy (wolfe8):

That's what I was waiting for, So look at each element on both sides. Add coefficients to the molecules so that the number of each elements is equal on both sides.

OpenStudy (anonymous):

ok sweet thanks

OpenStudy (wolfe8):

You're welcome.

OpenStudy (unklerhaukus):

C_12H_22O22+ O_2 => CO_2+ H_2O balance the carbons first there are twelve on the lefthand side what number do you have to multiply the CO_2 by to get twelve carbons on the righthand side ?

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