Balance this equation using redox half reaction
MnO4 (C:-1) +HSO3 (C:-1) + H (C:+1)-- SO4 (C:-2) + Mn (C:+2)

C: charge

Question

Balance this equation using redox half reaction
MnO4 (C:-1) +HSO3 (C:-1) + H (C:+1)--> SO4 (C:-2) + Mn (C:+2)

C: charge

anonymous · Answer

What i got was: 
MnO4 + 2HSO3 --> Mn + 2SO4 + 2H2O

is this right? cuz its seems right i just want to be sure, this is for a lab

anonymous · Answer

Full solution:
Reduction Equation: 6e + 8H + MnO4 ---> Mn + 4H2O
Oxidation Equation: (H2O + HSO3 ---> SO4 + 4H + 3e) *2
------------------------------------------------
6e + 8H + MnO4--> Mn + 4H2O                             I cancel out hydrogens and electrons
2H2O + 2HSO3--> Mn + 2SO4 + 2H2O+ 8H + 6e
---------------------------------------------
Final Answer: MnO4 +2HSO3---> Mn + 2 SO4 + 2H20

aaronq · Answer

it seems right, dude. next time write the charges it makes it easier to see, though i know it's a pain to format it. try learning $\LaTeX $

anonymous · Answer

alright thx