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Chemistry 19 Online
OpenStudy (anonymous):

What volume of 0.105 M HClO4 solution is needed to neutralize 54.00mL of 8.95×10−2 M NaOH?

OpenStudy (abb0t):

First, start by writing the balanced chemical equation, can you do that?

OpenStudy (anonymous):

Use M1V1= M2V2 So you'd get (0.105 M HClO4)(0.054L)=(8.95×10−2 M NaOH)(X)

OpenStudy (abb0t):

That's assuming the ratio is 1:1 @Atami

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