Question

Simplify i41

Answer 1

could this be \(i^{41}\) ?

Answer 2

yes

Answer 3

pattern is
\[i^0=1\\
i^1=i\\
i^2=-1\\
i^3=-i\\







i^4=1\]

Answer 4

take the integer remainder when you divide \(41\) by \(4\) to see which exponent to use

Answer 5

41 divided by 4 is 10.25

Answer 6

not 41 divided by 4, the remainder when you divide 41 by 4

Answer 7

4 goes in to 41 ten times with a remainder of 1
so
\[i^{41}=i^1\]

Answer 8

ohhhhh

Answer 9

thanks !

Answer 10

using exponents and i^2 =-1
( i^40)(i^1)