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Mathematics 13 Online
OpenStudy (anonymous):

How does e^(ln3)=3?

OpenStudy (zzr0ck3r):

\(a^{\log_a(x)}=x\)

OpenStudy (anonymous):

omg yes! i remember this now! how would that apply to e^(2ln5)

OpenStudy (zzr0ck3r):

By definition we have \(\large y=\log_a(x) \implies a^y=x\) so if we substitute in for y, we get \(\large x = a^y=a^{log_a(x)}\)

OpenStudy (zzr0ck3r):

we also have this property \[\log(x^y)=y\log(x)\] so \[e^{2\ln(5) }=e^{\ln(2^5)}=2^5 = 32\]

OpenStudy (anonymous):

wouldn't it be \[e ^{\ln(5^{2)}}\] ?

OpenStudy (zzr0ck3r):

yeah sorry

OpenStudy (zzr0ck3r):

so 5^2 = 25

OpenStudy (anonymous):

ahh ok i see it now :)

OpenStudy (zzr0ck3r):

\(e^{2\ln(5) }=e^{\ln(5^2)}=5^2 = 25\)

OpenStudy (zzr0ck3r):

long day....

OpenStudy (anonymous):

its fine! I understood :)

OpenStudy (anonymous):

I appreciate your help!

OpenStudy (zzr0ck3r):

np

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