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Physics 13 Online
OpenStudy (anonymous):

A monkey in a perch 20 m high in a tree drops a coconut above the head of a zoo keeper as he runs with a speed 1.5 m/s beneath the tree actually intending to hit the toes of the zoo keeper, how early in seconds should the coconut be dropped by the monkey?

OpenStudy (anonymous):

I have calculated the distance the zoo keeper runs from the point the coconut hits the ground. Found it to be 3.03m

OpenStudy (petiteme):

Do you know what you are looking for?

OpenStudy (anonymous):

Yes, but a bit confused.

OpenStudy (anonymous):

the zoo keeper runs 1.5m per second. So, at this instant the coconut should hit him, but how do I work out the time the monkey drops the coconut?

OpenStudy (anonymous):

well u kno for sure, if the monkey drops the coconut exactly when the man is RIGHT UNDER the monkey, the stone will fall behind.. yea? so .. now u need to calculate how early? correct?.. so say that he drops the stone, when the man is about x meters from the tree.. and it takes t seconds evaluate x and t!

OpenStudy (anonymous):

It depends if the zoo keeper has a gun or not.

OpenStudy (anonymous):

The coconut takes 2.02 s to fall from the tree. Assuming the monkey is not moving, he would then 2.02 seconds before the zoo keeper was directly under him. I cannot see how the zoo-keeper's speed comes into it.

OpenStudy (anonymous):

Question was kind of confusing at first, but I was able to piece it all together. The monkey has to drop the coconut 2.02 seconds earlier.\[h = \frac{ 1 }{ 2 }g t^{2}\] \[d=velocity \times time (t)\]

OpenStudy (anonymous):

Thank you @petiteme , @Mashy and @alanevans99 for your time.

OpenStudy (petiteme):

yw ^_^ hehe lol

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