Question

Can someone please help me? I dont know how to work this problem!

Perform the operation and leave the result in trigonometric form.

4(cos40deg+isin40deg)
-----------------------
3(cos160deg+isin160deg)

Answer 1

Thats divided btw.

Answer 2

\[\Large\bf\sf 3\left[\cos(4\cdot40)+i \sin(4\cdot40)\right]\]De'Moire's Theorem (I hope I spelled that right) allows us to write it like this:\[\Large\bf\sf 3\left[\cos40+i \sin40\right]^4\]Bringing the 4 outside as an exponent.
Does that identity look familiar?

Answer 3

The answer I got was
4(cos 40 + isin 40)^3
Is that correct?
Or is your answer correct?

Answer 4

Hmmm,\[\Large\bf\sf \cos n \theta+ i \sin n \theta \quad\ne\quad (\cos n \theta+i \sin n \theta)^n\]You've got to take the n out of our trig functions.
I have a feeling that's what you did.. hmm

Darn I gotta go to work D: sorry

Answer 5

Alright let me see. You have to take out the cos and the isin? I dont understand. Can you show me? I have other problems like this one to solve.

Answer 6

i take it you are dividing right?

Answer 7

the number out front stays \(\frac{4}{3}\) then subtract the angles
that is all

Answer 8

there are lots of ways to write it but your basic job is to compute \(40-160\)

Answer 9

I am still lost. I'm sorry. I dont like these problems, lol