find the 90th term of the sequence 9,18,27...
1st term: 9 2nd term: 18 3rd term: 27 So you can see that this pattern is the list of multiples of 9
the first term is equal to 1*9 = 9 the second term is equal to 2*9 = 18 the third term is equal to 3*9 = 27 etc etc
so its 810?
you nailed it
yay!:) how do i find the missing term of 5,__,27
Is this an arithmetic sequence? or geometric sequence?
arithmetic
let d be the common difference
so to get the next term, we add on d to get 5+d
To get the next term after that, we add on another d (5+d)+d = 5 + 2d This is equal to 27 since we know this 3rd term Therefore, 5+2d = 27 d = ??
11?
good
so the next term after 5 (the first term) is 5+d = 5+11 = 16
Notice how adding on another 11 gives us 16+11 = 27
how do you know if its arithmetic?
you just said it was when I asked you
I'm assuming they provided this information in the problem itself
a sequence is arithmetic when you add the same thing to each term to get the next term
no im on a different one now and it wants to know if its arithmetic or not
If its arithmetic you'll see that there's a common difference
so for instance, the sequence 1, 3, 5, 7, 9 is arithmetic because your'e adding 2 to each term to get the next term
the sequence 1, 3, 5, 7, 10 is NOT arithmetic because each term is found by adding 2 to the previous term...but jumping from 7 to 10 breaks this pattern
okay this is a new problem... 33,37,41 whats the 19th term... i know they have a difference of 4
first term: 33 common difference: 4
so a1 = 33 d = 4
an = a1 + d(n-1) an = 33 + 4(n-1) an = 33 + 4n-4 an = 4n + 29
So the nth term is an = 4n + 29
Notice for say term 2, n = 2 an = 4n + 29 a2 = 4(2) + 29 a2 = 8 + 29 a2 = 37 which matches up with the list
i got 105:)
There's a faster way instead of doing all of that. an = a1 + d(n – 1) you want to find the 19th term so you put a_19 = 33 + 4(19-1) a_19 = 33 + 4(18) a_19 = 33 + 72 a_19 = 105
105 is correct
what about this one?
nevermind i got 5
5 is correct, nice work
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