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Mathematics 10 Online
OpenStudy (anonymous):

math help?

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

a(n-1) is the term right before a(n) a(n+1) is the term right after a(n) if d is the common difference, then a(n-1) = a(n)-d a(n+1) = a(n)+d and taking the arithmetic mean of those two terms gives you [a(n-1)+a(n+1)]/2 [a(n)-d+a(n)+d]/2 [2a(n)]/2 a(n) So that proves that a(n) is the arithmetic mean of a(n-1) and a(n+1) To find the actual arithmetic mean, you simply add up the two values and divide by 2 So.. (5 + (-9))/2 (5 - 9)/2 -4/2 -2 is the arithmetic mean

OpenStudy (anonymous):

?

jimthompson5910 (jim_thompson5910):

what's the first term? What's the common difference?

OpenStudy (anonymous):

6 and d is 8

jimthompson5910 (jim_thompson5910):

good, so a1 = 6 d = 8

jimthompson5910 (jim_thompson5910):

Plug those into an = a1 + d(n-1) and simplify

OpenStudy (anonymous):

but im suppose to write the explicit formula for the answer..

jimthompson5910 (jim_thompson5910):

this will help you get that answer

jimthompson5910 (jim_thompson5910):

replace a1 with 6, replace d with 8 then distribute and combine like terms

OpenStudy (anonymous):

13n-12?

OpenStudy (anonymous):

i mean 14n-13?

jimthompson5910 (jim_thompson5910):

an = a1 + d(n-1) an = 6 + 8(n-1) an = 6 + 8n-8 an = ??

OpenStudy (anonymous):

2+8n?

jimthompson5910 (jim_thompson5910):

close, but no

OpenStudy (anonymous):

-2+8n?

jimthompson5910 (jim_thompson5910):

or 8n + (-2) or 8n - 2 8n - 2 is the most simplest in my opinion

OpenStudy (anonymous):

how do i wright a recursive formula?

OpenStudy (anonymous):

@johnweldon1993

jimthompson5910 (jim_thompson5910):

what term are you adding each time to get the next term?

jimthompson5910 (jim_thompson5910):

the site is being slow, so you'll have to be a bit (more) patient

OpenStudy (anonymous):

8

jimthompson5910 (jim_thompson5910):

so the recursive formula is basically nth term = (previous term) + 8 and you write it as \[\Large a_{n} = a_{n-1} + 8\] where a1 = 6

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

were you able to get anywhere with this one?

OpenStudy (anonymous):

no i wasnt

jimthompson5910 (jim_thompson5910):

what is the arithmetic mean of 2 and -14?

OpenStudy (anonymous):

-6?

jimthompson5910 (jim_thompson5910):

so that's a3

jimthompson5910 (jim_thompson5910):

a3 = -6

jimthompson5910 (jim_thompson5910):

now find the arithmetic mean of a1 and a3 to get a2 then find the arithmetic mean of a3 and a5 to get a4

OpenStudy (anonymous):

okay i got -2,-6,-10

jimthompson5910 (jim_thompson5910):

those are correct extra info: the common difference is -4 (ie we're adding -4 or subtracting 4 each time)

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

Solve for x (x+3937)/2 = 4327

jimthompson5910 (jim_thompson5910):

x is the salary of the unknown person Add this unknown salary to the other known individual salary ($3937) and then divide that result by 2 to get the average ($4327) produces that equation. Solving for x will get your answer.

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