Question

Did I simplify this correctly?

Answer 1

1/r + 1/ 1-r ....

Answer 2

= ....

Answer 3

\[\frac{ 2-2r }{ 1-r}\]

Answer 4

\[\frac{ 1 }{ r }+\frac{ 1 }{ 1-r } = \frac{ 2-2r }{ 1-r }\] that's what i got

Answer 5

is this correct?

Answer 6

nope.

to add fractions, their denominators must me the same.

to do so, multiply every term so that it becomes the common denominator, which in this case is r(1-r)

notice that we are multiplying by 1. :

\[\frac{ 1 }{ r } + \frac{ 1 }{ 1-r } = \frac{ 1 }{ r } \times \frac{ 1-r }{ 1-r } + \frac{ 1 }{ 1-r } \times \frac{ r }{ r } = \frac{ 1 - r + r }{ r(1-r) } = \frac{ 1 }{ r(1-r) }\]

Answer 7

ohh yeah I see

Answer 8

Thanks <3