If cot=2/5, sen<0, how much is cos?
So adyacent is 2, and the hip is sqrt of 29, right?
sen?
sin
sine*
OK, if sine is negative, what quadrent is it in?
3 or 4, right?
OK. So, it is in 3 or 4. Now, where could the cotangent be positive?
oh...in 4
Cotangent positive in 4? Ummm....
cot is adjacent/opposite...so adjacent should be positive...right?
oh...but sine is negative...so the opposite is negative, so adjacent needs to be negative!
This question seems to be using the unit circle definition. \(\cot\theta=\dfrac{\cos\theta}{\sin\theta}\) So for that to be positive, both the sine and cosine must have the same sign.
|dw:1392259809956:dw|
Ok. everything is understood until there
Have you done anything with the unit circle yet?
"oh...but sine is negative...so the opposite is negative, so adjacent needs to be negative!" And that IS correct.
See, there is a way to equate a right triangle to the unit circle... but not sure if you are using that. |dw:1392260088774:dw|
I have done it a long time ago, I know how to measure the trigonometric functions of a respective angle using the 45 triangles and the 90-60-30 triangles
Yep, we've done that before
OK, so, what do you think the answer would have to be then?
Well, then we would need to measure the hypotenuse...sqrt of 29
and then cos should be 2/sqrt29 ...but that's not a choice
negative
oh...then I multiply by sqrt of 29/sqrt of 29 and I get the answer :D
Negative :P
Ah, yah, you had to rationalize the denominator.
Yep :) forgot about that :P
Thanks a lot
np. Have fun!
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