OpenStudy (anonymous):
Carmen rides her bicycle at a constant rate to the market. When she rides her bicycle back home along the same route, she bikes at three-quarters the rate she biked to the market. At any given time, t, the distance biked can be calculated using the formula d = rt, where d represents distance and r represents rate. If the trip home takes 12 minutes longer than the trip to the market, how many minutes does it take Carmen to bike home?
OpenStudy (tkhunny):
Have you considered using Distance = Rate * Time? We have two trips. It is the same trip, both times, just in opposite directions. Distance Out = Distance Back She bikes at three-quarters the rate she biked to the market (3/4) Rate Out = Rate Back the trip home takes 12 minutes longer than the trip to the market, Time Out = Time Back + 12 min That's a lot of information. Getting anywhere?
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