Question

*question in the comments* a little help with this?

Answer 1

you can see the answer too, but I want to know how to do it :)

Answer 2

i HAVE TO FIND comon denominator right?

Answer 3

perimeter = side + side + side

Answer 4

and yes u have to find common denominator to add fractions :)

Answer 5

perimeter = \(\large \mathbb{\frac{5x}{2} + \frac{20}{x+4} + \frac{10}{x-4}}\)

Answer 6

5x/2 (x+4/x+4) + 20/x+4(2/2) + 10/x-4(-2/-2) am I doing it right so far?

Answer 7

you know, to get common denominator 2x+8 ?

Answer 8

am I even doing this correctly?

Answer 9

looks perfect, but let me put it in latex so it becomes reeadable..

Answer 10

perimeter = \(\large \mathbb{\frac{5x}{2} + \frac{20}{x+4} + \frac{10}{x-4}}\)

= \(\large \mathbb{\frac{5x}{2}\color{red}{\frac{x+4}{x+4}} + \frac{20}{x+4} \color{red}{\frac{2}{2}} + \frac{10}{x-4}\color{red}{\frac{2}{2}} }\)

Answer 11

u meant that right ?
just see that, denominators are not fully equal yet... u still need to work a bit

Answer 12

oh

Answer 13

perimeter = \(\large \mathbb{\frac{5x}{2} + \frac{20}{x+4} + \frac{10}{x-4}}\)

= \(\large \mathbb{\frac{5x}{2}\color{red}{\frac{x+4}{x+4}}\color{red}{\frac{x-4}{x-4}} + \frac{20}{x+4} \color{red}{\frac{2}{2}}\color{red}{\frac{x-4}{x-4}} + \frac{10}{x-4}\color{red}{\frac{2}{2}} \color{red}{\frac{x+4}{x+4}}}\)

Answer 14

how about now ?
take a good look at denominator for all 3 fractions...
do they look same now ?

Answer 15

yes! :D thanks so much <3

Answer 16

u sure ? u can work the rest and get to given answer ha ? :)

Answer 17

perimeter = \(\large \mathbb{\frac{5x}{2} + \frac{20}{x+4} + \frac{10}{x-4}}\)

= \(\large \mathbb{\frac{5x}{2}\color{red}{\frac{x+4}{x+4}}\color{red}{\frac{x-4}{x-4}} + \frac{20}{x+4} \color{red}{\frac{2}{2}}\color{red}{\frac{x-4}{x-4}} + \frac{10}{x-4}\color{red}{\frac{2}{2}} \color{red}{\frac{x+4}{x+4}}}\)

= \(\large \mathbb{\frac{5x*(x+4)(x-4) + 20*2(x-4) + 10*2(x+4)}{2(x+4)(x-4)} }\)

Answer 18

^^since the denominators are common, we can simply add the numerators

Answer 19

next, simplify the numerator