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Mathematics 19 Online
OpenStudy (anonymous):

Trig Derivative function! will give medals to all

OpenStudy (anonymous):

OpenStudy (anonymous):

you need to use quotient rule

OpenStudy (anonymous):

you only need to show it in simplified terms

OpenStudy (anonymous):

*not in simplified terms

OpenStudy (anonymous):

i got the answer

OpenStudy (anonymous):

(5*cos(x) + 1/(3*x^(2/3)))/(x*cos(x) + 5) - ((5*sin(x) + x^(1/3))*(cos(x) - x*sin(x)))/(x*cos(x) + 5)^2

OpenStudy (anonymous):

is -5457/2500

OpenStudy (anonymous):

\[f(x)=\frac{ 5\sin x+\sqrt[3]{x} }{x \sec x+5 }=\frac{ 5\sin x+x ^{\frac{ 1 }{ 3 }} }{x \sec x+5 }\] \[f \prime \left( x \right)=\frac{ \left( x \sec x+5 \right)\left( 5 \cos x+\frac{ 1 }{3 }x ^{\frac{ -2 }{ 3 }} \right)-\left( 5 \sin x+x ^{\frac{ 1 }{3 }} \right)\left\{ x \sec x \tan x+\sec x+0 \right\} }{ \left( x \sec x+5 \right)^{2} }\] \[put x=\pi,\sin \pi=0,\cos \pi=-1,\tan \pi=0,\sec \pi=-1\]

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