Question

g = R((pi X rpm)/30)^2 / 9.81 m/sec^2

Answer 1

if R = 100 m

Answer 2

What is this?

Answer 3

The question was ... "If inside a space ship orbiting Earth, how fast would the ship need to spin in order for a person inside to experience earth like gravity?" I was given this formula as an answer.

Answer 4

Then I think you're looking for X. g=9.8 m/s^2 Just solve for X

Answer 5

My guess is Gravity = 100 m (3.14 x RPM) divided by 30)^2 divided by 9.81 m divided by sec^2

Answer 6

(x) is times, as in 2 "times" 2 = 5

Answer 7

no pun intended

Answer 8

no the pun was intended lol

Answer 9

2x2=4

Answer 10

Hmm. So you're just putting 100 and 9.8 in. Remember the square applies to the whole pi*RPM. Then solve for RPM.

Answer 11

Yes I am trying to find the speed of rotation needed for earth like gravity in orbit. The question here is how to I solve for RPM?

Answer 12

Ah so you need help on the math. Well,
1) multiply both sides with 9.8
2) divide both sides with R
3) square root both sides
4 multiply both sides with 30
5) divide both sides with pi

Answer 13

thanks

Answer 14

You're welcome. Did it work?

Answer 15

one minute

Answer 16

would i multiply 9.81 by 9.81 on the left?

Answer 17

I'm guessing that was something obvious

Answer 18

Yes you do

Answer 19

would I be dividing 100 into 9.81 or 9.81 into 100?