Vectors Problem:Forces of 60 pounds and 100 pounds have a resultant force of 125 pounds. Find the angle between the two forces.
to my knowledge, one more data is missing. But still I can be wrong
nope im sure this is all, i managed to solve this before but forgot how to
ahaa you can represent the forces by the sides of a triangle and then it's a matter of using sine rule and cosine rule
how would you do that?
so the sides are 60,100,125
just realized law of cosines
and the cosine rule is a^2=b^2+c^2-(bc)costheta
yeah, so I guess you got it now
thanks for the question as well
ive been trying to use vector properties to solve this
wait 1 sec the resultant force isnt the 3rd side of the triangle
|dw:1392273857194:dw| \[c^2=a^2+b^2-2ab\cos\theta\]\[125^2=100^2+60^2-2(100)(60)\cos\theta\]\[2025=-12000\cos\theta\]You can do the rest...
@d3v13 one of us has a faulty formulation of the law of cosines
Join our real-time social learning platform and learn together with your friends!