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Mathematics 17 Online
OpenStudy (anonymous):

(x-y)^2 = 1

OpenStudy (anonymous):

are u from Sri Lanka?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

ah nice to meet you then so with what u need help

OpenStudy (anonymous):

\[x-y= \pm1\]

OpenStudy (anonymous):

can u pls gv me derivative to (x - y)^2 = 1

OpenStudy (anonymous):

with respect to what?

OpenStudy (anonymous):

to y

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

\[(x-y)^{2}= x ^{2}+y ^{2}-2xy=1\]

OpenStudy (anonymous):

let me denote dx/dy=x' since you want to derivate with respect to y

OpenStudy (anonymous):

\[2xx' +2y-2(x'y+x)=0\]

OpenStudy (anonymous):

so this is the first derivative with respect to y

OpenStudy (anonymous):

did I answer your question

OpenStudy (anonymous):

sorry for this late reply and ya u gave the answer :)

OpenStudy (anonymous):

what is the derivative of 7955.6e^-0.0458/t

OpenStudy (mathmale):

Would you mind posting each question separately? What is the derivative of e^t? of e^(-t)? To find the derivative of the function you've just given, you'll have to use (1) the rule for the derivative of e^u and (2) the chain rule, since your exponent is in itself a function, and (3) the power rule (since 1/x is a power of x.

OpenStudy (anonymous):

(7955.6)e^(-0.0458/t)

OpenStudy (mathmale):

Don't understand. Was that meant to be a question? an answer? a review? Please always include instructions or explanations with expressions such as this one. I'd be glad to help you, but do hope you'll answer my questions first.

OpenStudy (anonymous):

this is a question and its like this v = (7955.6)e^(-0.0458/t) and i have to find dv/dt it means v' (v's derivation)

OpenStudy (mathmale):

I asked you earlier: What is the derivative of e^t? of e^(-t)? To find the derivative of the function you've just given, you'll have to use (1) the rule for the derivative of e^u and (2) the chain rule, since your exponent is in itself a function, and (3) the power rule (since 1/x is a power of x. Mind answering? Then I'd be in a better position (as well as more willing) to address your question about differentiating v(t).

OpenStudy (mathmale):

Example: If y = 5 e^(2t), the derivative would be dy/dt = 5 e^(2t) * 2 = 10*e^(2t). In obtaining this result, I used: (1) the rule for the derivative of e^u and (2) the chain rule, since your exponent is in itself a function, and (3) the power rule. Hope this makes sense to you; if not, ask questions. Better to learn from a simple example than from a more complicated problem.

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