Ask your own question, for FREE!
Calculus1 12 Online
OpenStudy (anonymous):

Determine the point at which the graph of the function below has a horizontal tangent line. (If the function has no horizontal tangent line, enter NONE.) y =x3 + 3x

OpenStudy (anonymous):

Slope of a horizontal line is zero. Derivative of the given function is 3x^2 + 3 which has no real roots. So there are NO horizontal tangents to the given function.

OpenStudy (anonymous):

3x^2+3

OpenStudy (anonymous):

right

OpenStudy (anonymous):

Determine the point at which the graph of the function below has a horizontal tangent line. (If the function has no horizontal tangent line, enter NONE.) y =x3 + 3x (x, y)

OpenStudy (anonymous):

Right the derivative is 3x^2 + 3 and when you equate it to zero (because the derivative means slope, and slope should be zero for a horizontal line), you get 3x^2 + 3 = 0 3x^2 = -3 x^2 = -1, which gives complex (non real) roots. Since the derivative can't equal zero for any value of x, that means there is no horizontal tangent to the given function for any real value of x.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
23 hours ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
1 day ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!