HELP
onsider the following function.
f(t) = 2t2 − 1
Find the average rate of change of the function below over the interval [5, 5.1].

Compare this average rate of change with the instantaneous rates of change at the endpoints of the interval.
(at t = 5)
(at t = 5.1)

Question

HELP 
onsider the following function.
f(t) = 2t2 − 1
Find the average rate of change of the function below over the interval [5, 5.1].


Compare this average rate of change with the instantaneous rates of change at the endpoints of the interval.
(at t = 5)
(at t = 5.1)

whpalmer4 · Answer

average rate of change from $a$ to $b$ is $$\frac{f(b)-f(a)}{b-a}$$

anonymous · Answer

its to hard for me :/

whpalmer4 · Answer

What's hard?  you can evaluate $2t^2-1$ for various values of $t$, can't you?

whpalmer4 · Answer

$$f(t) = 2t^2-1$$$$f(5) = 2(5)^2-1 = 2(25)-1 = 50-1=49$$
$$f(5.1) = $$?

anonymous · Answer

f(5.1)= 51.02

whpalmer4 · Answer

Good!  Now we know $f(5) = 49$ and $f(5.1) = 51.02$We can find the average rate of change from t = 5 to t = 5.1 by my formula:

$$m = \frac{f(b)-f(a)}{b-a}$$where $b = 5.1,\, b=5$
What is the value of $m$?