can anyone please help me with trigonometry?? I've been asking and asking through messages and no one replies
tis easier with an specific posting
Describe how the graphs of functions f and g are related : f(x) = 2 cos(pi x) and g(x) = 2cos (2pi x)
have you covered function transformations? like for say a quadratic function or a linear one?
and second question : Determine the period,domain,range,zeros, and asymptotes (if any). Then sketch graph of function y = -3tan (1/2 x)
yes well the basics is what I know for example y = Asin(B(x+/- c)) +/- D
so can you help me with either question please?
I've done about 15 other questions just need to finish those two
oh and amplitude and period of y = -sin (x - pi/4) + 2
that's it
well, for one f(x) and g(x) share the same amplitude
and for another, g(x) is the same as f(x), just SHRUNKEN a bit due to its phase/horizontal shift \(\bf f(x) = 2 cos({\color{blue}{ \pi }}x) \qquad g(x) = 2cos ({\color{blue}{ 2\pi}} x)\\ \quad \\ \textit{phase shift}\quad f(x)\implies \cfrac{2\pi}{{\color{blue}{ \pi }}}\qquad g(x)\implies \cfrac{2\pi}{{\color{blue}{ 2\pi}}}\)
wait so there is a phase shift?
I thought that was period when you do 2pi/ B
ohh right, it's the period... .I meant... .thus is SHRUNKEN
other than that... they're the same function
so g(x) is shrunken version of f(x)?
hi @ranga !
yes
for how the graphs are related I have " Neither experience phase shift or vertical translation". "Both have same amplitude of 2." and "Period of f(x) = 2 and period of g(x) = 1. Anything else I should add?
oh and g(x) is shrunken version of f(x). Wait horizontally or vertically?
the period is being changed from g(x) so it'll shrink from |dw:1392327255982:dw|
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