Two motor-cyclists A and B are travelling in the same direction in different lanes on a motorway. a has a constant acceleration of 0.5ms^-2 and B has a constant speed of 30ms^-1. At time t=0, A is 375 m ahead of B is travelling with speed 10ms^-1. The motion of the two motion of the two motor-cyclists may be modeled by that two particles moving along parallel straight lines. B overtakes A at t=T1 where the time is measured in seconds Show that t=T1 is a solution of the equation t^2-80t+1500=0 Interpret the other solution, t=T2 of this equation Find the values of T1 and T2 and hence find
find the speed of A at these times
no
im confused... im sorry >.<
its ok :)
ok.. im sorry
its okay and thank you for trying your best
solve the given equation : t^2-80t+1500=0
that gives u the two times t1, t2, at which both of them meet
but how could i determine this equation t^2-80t+1500=0
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