Mathematics
14 Online
OpenStudy (ammarah):
Solve. Check for extraneous solutions.
x^2/x+5=4/x+5
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
start by multiplying both sides wid (x+5)
ganeshie8 (ganeshie8):
that gets rid of the denominators
OpenStudy (ammarah):
so far i just cross multiplied and got x^3+5x^=4x+20
OpenStudy (ammarah):
wait so is the answer x= +or -2?
OpenStudy (ammarah):
@ganeshie8
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
\(\large \frac{x^2}{x+5}=\frac{4}{x+5}\)
ganeshie8 (ganeshie8):
multiplying (x+5) both sides gives u :
\(\large x^2 = 4\)
ganeshie8 (ganeshie8):
taking square-root gives :
\(\large x = \pm 2\)
ganeshie8 (ganeshie8):
so, you're right !!
OpenStudy (ammarah):
ok great i have another one im confused on
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
And, do check if they satisfy the original equation or not.
OpenStudy (ammarah):
how y plugging in 0?
OpenStudy (ammarah):
by*
ganeshie8 (ganeshie8):
if they DONT satisfy the original equation,
then they are called 'extraneous solutions'
ganeshie8 (ganeshie8):
just plugin x = 2 in the given equation,
and see if u get same thing on both sides
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ammarah):
ok its satisfies
ganeshie8 (ganeshie8):
wat about x = -2 ?
OpenStudy (ammarah):
no
ganeshie8 (ganeshie8):
why no,
i see x=-2 also satisfies
OpenStudy (ammarah):
oops i mean yes
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ammarah):
both satisfy
ganeshie8 (ganeshie8):
cool :)
so both are good solutions oly.
they're not extraneous/errenous/bad in any way ok
OpenStudy (ammarah):
how about this one:
3/x+2=x-3/2x+4
ganeshie8 (ganeshie8):
look at right side denominator,
can u factor the GCF ?
OpenStudy (ammarah):
i simplified 2(x+2)
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
\(\large \frac{3}{x+2}=\frac{x-3}{2x+4}\)
\(\large \frac{3}{x+2}=\frac{x-3}{2(x+2)}\)
\(\large 3 = \frac{x-3}{2}\)
ganeshie8 (ganeshie8):
yes, ive cancelled the x+2 both sides. looks ok ?
OpenStudy (ammarah):
what how?
ganeshie8 (ganeshie8):
at step 2 :
look at denominators on both sides
x+2 is there on both sides right ?
OpenStudy (ammarah):
ohhh i get it
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
good :)
OpenStudy (ammarah):
from here do u just cross multily
ganeshie8 (ganeshie8):
yes !
OpenStudy (ammarah):
x=9
ganeshie8 (ganeshie8):
Perfect !
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
u need to check if it is good/bad
OpenStudy (ammarah):
bad
ganeshie8 (ganeshie8):
nope. it is good
OpenStudy (ammarah):
wait nvm
ganeshie8 (ganeshie8):
plug x = 9 in the original equation
and see if it satisfies
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ammarah):
yea my bad
ganeshie8 (ganeshie8):
lol okie doke
OpenStudy (ammarah):
i dont get this one:
3/x-1+5/x+1=8x+5/x^-1
OpenStudy (ammarah):
theres like two parts to it
OpenStudy (ammarah):
oh please dont leave i have a couple more prob @ganeshie8
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
\(\large \frac{3}{x-1}+\frac{5}{x+1}=\frac{8x+5}{x-1}
\)
ganeshie8 (ganeshie8):
like that ?
OpenStudy (ammarah):
i mean x^-1
ganeshie8 (ganeshie8):
then it must be more likely a typo in ur question..
OpenStudy (ammarah):
why
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
this doesnt look simple :o
OpenStudy (ammarah):
fine r u good with fractions? i have two questions with complex fractions
OpenStudy (ammarah):
ill open another window k?
ganeshie8 (ganeshie8):
this question il skip... ive no clue how to do it in simple way...