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Mathematics 17 Online
OpenStudy (timaashorty):

Please help me and show the steps.

OpenStudy (shamil98):

complete the squares to get it in this form: (x-h)^2 + (y-k)^2 = r^2

OpenStudy (tkhunny):

Have you considered completing the square twice? x^2 - 4x + _____ + y^2 + 10y + _____ = 7 + _____ + _____

OpenStudy (tkhunny):

Ponder this, deep in your heart: \((a+b)^{2} = a^{2} + 2ab + b^{2}\) THAT is how to do it.

OpenStudy (timaashorty):

x^2 - 4x + 4 + y^2 + 10y + 25 = 7 + 4 + 25 ?

OpenStudy (zale101):

yes

OpenStudy (timaashorty):

Thanks zale and then what do I do ?

OpenStudy (zale101):

now add 7+4+25

OpenStudy (zale101):

36

OpenStudy (zale101):

(x^2−4x+4)+(y^2+10y+25)=7+4+25 (x^2−4x+4)+(y^2+10y+25)=36 then factor each to get the circle equation (x^2−4x+4)=(x-2)^2 (y^2+10y+25)(x+5)^2 (x−2)^2+(y+5)^2=36 so the center is (2,-5) and the radius is the sqrt of 36 which is 6 (x−2)^2+(y+5)^2=6^2

OpenStudy (timaashorty):

Omg thank you so much zale!

OpenStudy (zale101):

np, @shamil98 and @tkhunny did an awesome work

OpenStudy (timaashorty):

thanks to them too c;

OpenStudy (zale101):

:)

OpenStudy (tkhunny):

You found the magic numbers so that it would be a perfect square. Do not hesitate to write it as one after you complete the square.

OpenStudy (timaashorty):

Haha thankyou tkhunny [:

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