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OpenStudy (shamil98):
complete the squares to get it in this form:
(x-h)^2 + (y-k)^2 = r^2
OpenStudy (tkhunny):
Have you considered completing the square twice?
x^2 - 4x + _____ + y^2 + 10y + _____ = 7 + _____ + _____
OpenStudy (tkhunny):
Ponder this, deep in your heart: \((a+b)^{2} = a^{2} + 2ab + b^{2}\)
THAT is how to do it.
OpenStudy (timaashorty):
x^2 - 4x + 4 + y^2 + 10y + 25 = 7 + 4 + 25 ?
OpenStudy (zale101):
yes
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OpenStudy (timaashorty):
Thanks zale and then what do I do ?
OpenStudy (zale101):
now add 7+4+25
OpenStudy (zale101):
36
OpenStudy (zale101):
(x^2−4x+4)+(y^2+10y+25)=7+4+25
(x^2−4x+4)+(y^2+10y+25)=36
then factor each to get the circle equation
(x^2−4x+4)=(x-2)^2
(y^2+10y+25)(x+5)^2
(x−2)^2+(y+5)^2=36
so the center is (2,-5)
and the radius is the sqrt of 36 which is 6
(x−2)^2+(y+5)^2=6^2
OpenStudy (timaashorty):
Omg thank you so much zale!
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OpenStudy (zale101):
np, @shamil98 and @tkhunny did an awesome work
OpenStudy (timaashorty):
thanks to them too c;
OpenStudy (zale101):
:)
OpenStudy (tkhunny):
You found the magic numbers so that it would be a perfect square. Do not hesitate to write it as one after you complete the square.