Find all values of x between 0 and 4pi Cos(x)= -0.6591
Could someone please explain it to me. Thank you
use ur calculator and find Cos^-1 -0.6591 cause cos <0 so im sure that X will be at Quadrant II or III
I did that but there are 3 other values I need to find within the 0 and 4 pi restriction
How can I find the other three?
What is the rule I need to follow? Cheers
\(\large \mathbb{\cos (x) = \cos(x + 2\pi ) }\)
that gives u 2nd solution
I don't get it
wat did u get for first value ?
Where did you come up with cosx = cos(x+2pi)
from many places. for now u can think of it like this : period of cosx = 2pi, so it repeats every 2pi.
I got 2.290
yes, use the given property now. second solution = \(2.29 + 2\pi\)
if x is a solution, then x+2pi is also a solution. cuz cos(x) repeats every 2pi.
if that makes any sense..
I see what about the other two values?
It does
good :) for other two values, use another property : \(\large \cos(x) = \cos(-x)\)
let me show it in a picture, so it makes sense why this is true.
u familiar wid 'unit circle' definition of trig functions ?
Yep
then its easy for u,
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