1^2 + 4^2 + 7^2 + ... + (3n - 2)^2 = [n(6n^2 - 3n - 1)]/2
induction?
Yeah. :/
sec
Okay! :)
would take way to long to type it. ask if you have questions. note how easy it is if you use summation notation.
Thank you so much. I've been working on this problem all day! I think that I actually understand induction based on how you wrote it out! Thank you so much again!
u LARS ?
Who the hell are u?
You are such a loser ** get a life *
Bye!
@_Unknown_17 Excuse me... Who are you?
np @Mrbonez321 just think of dominoes. this method will work on all the summation ones, and will help you get a better understanding of induction, i agree.
@zzr0ck3r Thank you for your help. I just have a quick question. On the foil, you got 6n^3 + 15n^2 + 11n + 2... But i dont understand where you got the 15n^2 from...
Ohhh i don't wanna talk! bye !
dont worry about the douchebags, there are plenty on the site.
on the rhs or the lhs?
LHS
are you talking about after this step 9n^2+6n+1+(n(6n^2-3n-1)/2)
Yes.
(9n^2+6n+1)+(n(6n^2-3n-1)/2) we need a common denom of 2, so we multiply 9n^2+6n+1 (top/bottom) by 2 (18n^2+12n+2)/2 now we have (18n^2+12n+2)/2 +(n(6n^2-3n-1)/2) = [(18n^2+12n+2)+(n(6n^2-3n-1)]/2 = [18n^2+12n+2+6n^3-3n^2-n]/2 = [6n^3 + 18n^2-3n^2+12n-11n+2]/2 = [6n^3+15n+11n+2]/2
Oh!!!! I forgot to multiply by two on the 9n^2 +6n+1 part!!! Thank you so much!!!
np
a+(b/c) = (ac+b)/c
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