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\[\frac{ \sqrt{6} }{ 4-\sqrt{6} }\]
First of all, you want the conjugate.
The conjugate if \(a+\sqrt{b}\) is \(a-\sqrt{b}\) and vice versa.
So we want the conjugate of \(4-\sqrt{6}\)
What do you think it would be?
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Guess
4+ \[\sqrt{6}\] ?
Yes
Now multiply the top and bottom by the conjugate.
It turns out that: \((a+\sqrt b)(a-\sqrt b) = a^2-b\)
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So we will get rid of square roots in the denominator at least.
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