Question

Calculate the area of triangle ABC with altitude CD, given A (6, -2), B (1, 3), C (5, 5), and D (2, 2). (5 points)
Select one:
a. 12 square units
b. 13 square units
c. 13 square units
d. 15 square units

Answer 1

@timo86m @iambatman

Answer 2

base * height

Answer 3

what that makes no sense

Answer 4

^ thats the area of a rectangle not a triangle, triangle is 1/2bh

Answer 5

oh yeah, base * height * 1/2

Answer 6

where is the base and the height

Answer 7

Sorry guys I'm helping someone else out right now, I'll get back to you later, if you still need help.

Answer 8

Here is what the triangle ABC looks like when you plot it on an xy coordinate grid (see attached)

Answer 9

so you can see that AB is the base and CD is the height

Answer 10

\(\bf \textit{Area of a Triangle}\cfrac{base\cdot height}{2}\implies \cfrac{AB\cdot CD}{2}\\ \quad \\
recall \\ \quad \\

\textit{distance between 2 points}\\ \quad \\
\qquad
d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}
\)

Answer 11

\(\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
A&({\color{red}{ 6}}\quad ,&{\color{blue}{ -2}})\quad B&({\color{red}{ 1}}\quad ,&{\color{blue}{ 3}})\\
C&({\color{red}{ 5}}\quad ,&{\color{blue}{ 5}})\quad D&({\color{red}{ 2}}\quad ,&{\color{blue}{ 2}})
\end{array}\qquad
d = \sqrt{({\color{red}{ x_2}}-{\color{red}{ x_1}})^2 + ({\color{blue}{ y_2}}-{\color{blue}{ y_1}})^2}\)