Question

Calculus help?

The position of a function is given by s(t) = 4t^2 + 2t + 3, where s is measured in feet and t in seconds. Find the velocity of the object at time t = 2 seconds. Include units in your answer

Answer 1

Do you know how to calculate derivatives?

Answer 2

yes, he does

Answer 3

velocity is the derivative of position

Answer 4

All they want is \(s'(2)\). Since \(v(t)=s'(t)\)

Answer 5

the derivative is 8t + 2

Answer 6

thats it?

Answer 7

You have to let \(t=2\).

Answer 8

so its 8(2)+2 = 18

Answer 9

feets/sec

Answer 10

right

Answer 11

thank you. I'd forgotten that!